Answer:
636.86 K
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T1) = 333 K
Initial pressure (P1) = 4 atm
Final pressure (P2) = 7.65 atm
Final temperature (T2) =?
NOTE: The volume is constant.
Since the volume is constant, we can obtain the new temperature the gas by using the following formula as illustrated below:
P1 /T1 = P2 /T2
4/333 = 7.65/T2
Cross multiply
4 × T2 = 333 × 7.65
4 × T2 = 2547.45
Divide both side by 4
T2 = 2547.45 / 4
T2 = 636.86 K
Therefore, the new temperature of the gas is 636.86 K
Answer:
a. The second run will be faster.
d. The second run has twice the surface area.
Explanation:
The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.
The area of the 10.0 cm³-sphere is:
The area of each 1.25 cm³-sphere is:
The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²
The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00
Since the surface area is doubled, the second run will be faster.
The answer is false. Hope this helps
It's asking what are the conditions of the water when the three types of fishes overlap. the three kids of fishes overlap over in the middle which is D. mild temperatures, some suspended particles, flows at medium speed.
C both are very reactive i guess
