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Answer:
B
Step-by-step explanation:
The red graph is a horizontal translation of 5 units left followed by a reflection in the x- axis.
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift to the left of a units
• If a < 0 then a shift to the right of a units
The black graph is shifted 5 units left, thus
f(x) → f(x + 5)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note that the y- coordinate of the image is the negative of the original
Note also that = - y, thus
= f(x + 5) → B
Use Law of Cooling:
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42
Substituting k back into cooling equation gives:
At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
Solve for x:
Sub back into original cooling equation, x = T(t)
Solve for t:
This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM