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mariarad [96]
3 years ago
9

Find m∠MON I have a hard time with theses

Mathematics
1 answer:
fredd [130]3 years ago
3 0

Answer:

m∠MON = 15°

Step-by-step explanation:

The given parameters are;

m∠LON = 77°

m∠LOM = 9·x + 44°

m∠MON = 6·x + 3°

By angle addition postulate, we have;

m∠LON = m∠LOM + m∠MON

Therefore, by substituting the known values, we have;

∴ 77° = 9·x + 44° + 6·x + 3°

77° = 9·x + 44° + 6·x + 3° = 15·x + 47°

77° = 15·x + 47°

77° - 47° = 15·x

15·x = 77° - 47° = 30°

15·x = 30°

x = 30°/15 = 2°

x = 2°

Given that m∠MON = 6·x + 3° and x = 2°, we have;

m∠MON = 6 × 2° + 3° = 12° + 3° = 15°

m∠MON = 15°.

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<u>Now, let's find the surface area of the rectangular prism.</u>

  • 2(18 x 9) + 2(6 x 9) + 2(6 x 18)
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<u>Now, add both the surface areas to find the surface area of the figure.</u>

  • 288 + 648 = Surface area of figure
  • => 936 ft² = Surface area of figure

The surface area of the figure is 936 ft².

7 0
2 years ago
What is -2/3x+1/3+x=2/5? thanks.
OverLord2011 [107]
-2/3x +1/3 +x = 2/5
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