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astraxan [27]
3 years ago
15

(6u-7c-6)+(-2u+4c) find the sum and express it in simplest form

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

(6u)+(-2u)=4u

(-7c)+(4c)=-3c

6=6

4u-3c+6

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Five years ago alex was 12 times as old as tom alex is 41 now how old is tom now
anastassius [24]

Step-by-step explanation:

I think this will help you. Thanks.

8 0
3 years ago
The constraints of a problem are listed below. What are the vertices of the feasible region?
Luda [366]

Answer: option 1.

Explanation:

feasible region is that region which is formed by the lines of constraints.

feasible region is shaded in the attached graph

inequalities becomes equalities to draw the graph

and lines will head towards the origin if constraint satisfied by putting x= 0, y=0

and on the contrary lines will move away from origin when condition of constraint does not satisfied.

3 0
3 years ago
Read 2 more answers
A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine co
seraphim [82]

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

7 0
3 years ago
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Nu is designing a rectangular sandbox.The bottomm is 16 square feet.Which dimensions require the least amount of materail for th
zzz [600]

Given Information:  

Area of rectangle = 16 square feet

Required Information:  

Least amount of material = ?

Answer:

x = 4 ft and y = 4 ft

Step-by-step explanation:

We know that a rectangle has area = xy and perimeter = 2x + 2y

We want to use least amount of material to design the sandbox which means we want to minimize the perimeter which can be done by taking the derivative of perimeter and then setting it equal to 0.

So we have

xy = 16  

y = 16/x

p = 2x + 2y

put the value of y into the equation of perimeter

p = 2x + 2(16/x)

p = 2x + 32/x

Take derivative with respect to x

d/dt (2x + 32/x)

2 - 32/x²

set the derivative equal to zero to minimize the perimeter

2 - 32/x² = 0

32/x² = 2

x² = 32/2

x² = 16

x = \sqrt{16} = 4 ft

put the value of x into equation xy = 16

(4)y = 16

y = 16/4

y = 4 ft

So the dimensions are x = 4 ft and y = 4 ft in order to use least amount of material.

Verification:

xy = 16

4*4 = 16

16 = 16 (satisfied)

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