Answer:
a) Total of ATP produced in glycolysis is equal to 2
ATP produced:
i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)
ii) phosphoenolpyruvate→pyruvate (2 ATP are produced)
b) 26 pyruvate molecules.
Explanation:
a) Glycolysis consists of two steps in which ATP is consumed and two steps in which ATP is released.
ATP produced = 4
ATP consumed = 2
The total of ATP produced in glycolysis is equal to 2 (4-2)
ATP produced:
i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)
ii) phosphoenolpyruvate → pyruvate (2 ATP are produced)
b) In the sixth step of glycolysis, inorganic phosphate molecules are consumed:
glyceraldehyde-3‑phosphate → 1,3‑bisphosphoglycerate
2 pi are added in glycolysis. As each glucose molecule undergoes glycolysis, the pi required by the 13 glocosa molecules is 26 (13 * 2). Glycolysis of each glucose produces 3 pyruvates, so 13 glucose molecules will produce 26 pyruvate molecules.
Asexual reproduction is when a cell can reproduce by itself, it can be done through more ways than just fission, and it is very efficient. The answer is A) it occurs in most prokaryotes
I just did it and the answer is Row 3.
Answer:that it allows us to convert very large or very small numbers into much more manageable sizes. When these numbers are in scientific notation, it is much easier to work with them. Scientific notation is also important because it ensures calculations that involve large numbers are still accurate.
Explanation: