Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.
1 answer:
Answer:
Hi,
a=b+3
Step-by-step explanation:
Thus:
c+2b+8-4a=c-a-b-1
3b-3a=-9
<u>a=b+3</u>
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