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3 years ago

In quadrilateral ABCD,AB produced is perpendicular to DC produced.If A=44° and C=148°,calculate D and B.

1 answer:

5 0

Let AB extended intersect DC extended at point E
We now have right triangle BEC with E = 90 degrees 

For triangle BEC: 
Exterior angle at E = 90 
Exterior angle at C = 148 (given) 
Exterior angle of all polygons add up to 360 degrees 
Exterior angle at B = 360−148−90 = 122 

So in quadrilateral ABCD 
B = 122 
D = 360−44−148−122 = 46

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3 years ago

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3 years ago

Use the quadratic formula to solve the equation 2x^2+2x-4=0

const2013 [10]

Answer:

Step-by-step explanation:

The quadratic formula for the quadratic equation ax² + bx + c = 0:

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$a=1,\ b=1,\ c=-2$

Substitute:

$x=\dfrac{-1\pm\sqrt{1^2-4(1)(-2)}}{2(1)}=\dfrac{-1\pm\sqrt{9}}{2}=\dfrac{-1\pm3}{2}\\\\x_1=\dfrac{-1-3}{2}=\dfrac{-4}{2}=-2\\\\x_2=\dfrac{-1+3}{2}=\dfrac{2}{2}=1$

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3 years ago