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enot [183]
2 years ago
6

Which number line represents the solution set for the inequality 2x-62 6(x-2) + 8?

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
4 0
The THIRD number line represents the solution of that inequality.
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Anarel [89]

Answer:

\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}}} \, dx = \infty

General Formulas and Concepts:

<u>Algebra I</u>

  • Exponential Rule [Rewrite]:                                                                           \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Integrals

  • Definite Integrals

Integration Constant C

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                         \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

U-Substitution

U-Solve

Improper Integrals

Exponential Integral Function:                                                                              \displaystyle \int {\frac{e^x}{x}} \, dx = Ei(x) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \int\limits^1_0 {\frac{e^{-x^2}}{x} \, dx
  2. [Integral] Rewrite [Improper Integral]:                                                         \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \int\limits^1_a {\frac{e^{-x^2}}{x} \, dx

<u>Step 3: Integrate Pt. 2</u>

<em>Identify variables for u-substitution.</em>

  1. Set:                                                                                                                 \displaystyle u = -x^2
  2. Differentiate [Basic Power Rule]:                                                                 \displaystyle \frac{du}{dx} = -2x
  3. [Derivative] Rewrite:                                                                                     \displaystyle du = -2x \ dx

<em>Rewrite u-substitution to format u-solve.</em>

  1. Rewrite <em>du</em>:                                                                                                     \displaystyle dx = \frac{-1}{2x} \ dx

<u>Step 4: Integrate Pt. 3</u>

  1. [Integral] Rewrite [Integration Property - Multiplied Constant]:                 \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {-\frac{e^{-x^2}}{x} \, dx
  2. [Integral] Substitute in variables:                                                                 \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {\frac{e^{u}}{-2u} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:                 \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}\int\limits^1_a {\frac{e^{u}}{u} \, du
  4. [Integral] Substitute [Exponential Integral Function]:                                 \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(u)] \bigg| \limits^1_a
  5. Back-Substitute:                                                                                             \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-x^2)] \bigg| \limits^1_a
  6. Evaluate [Integration Rule - FTC 1]:                                                             \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-1) - Ei(a)]
  7. Simplify:                                                                                                         \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{Ei(-1) - Ei(a)}{2}
  8. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \infty

∴  \displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx  diverges.

Topic: Multivariable Calculus

7 0
3 years ago
3m^2 + 2p^2 - 15 when m=3 and p =10
ArbitrLikvidat [17]
3*3^2+2*10^2-15=212
The answer is 212
3 0
3 years ago
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