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Anvisha [2.4K]
3 years ago
13

Please help me solve this, and show your work

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

6r+5=11r\ \ \ \ |\text{subtract 6r from both sides}\\\\5=5r\ \ \ \ |\text{divide both sides by 5}\\\\\boxed{r=1}\\-------------------------\\\dfrac{2x-4}{2}=6x+3\\\\\dfrac{2x}{2}-\dfrac{4}{2}=6x+3\\\\x-2=6x+3\ \ \ \ \ |\text{add 2 to both sides}\\\\x=6x+5\ \ \ \ |\text{subtract 6x from both sides}\\\\-5x=5\ \ \ \ \ |\text{divide both sides by -5}\\\\\boxed{x=-1}

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if the length of the rectangle is twice the width and the perimeter of the rectangle is 30 centimeters what is the length of the
Dominik [7]
If the perimeter equals 30 and the length is twice the width, then the length is equal to 20 and the width is equal to 10.

7 0
4 years ago
A line passes through the points (1, 4) and (3,-4). Which is the equation of the line?
andrew-mc [135]

Answer:

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Step-by-step explanation:

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3 years ago
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Anuta_ua [19.1K]

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Step-by-step explanation:

4 0
3 years ago
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Anna35 [415]
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5 0
4 years ago
Solve for x in the equation 2x^2-4x-9=29
Andrews [41]

Answer:

x = 1  ±2sqrt(5)

Step-by-step explanation:

2x^2-4x-9=29

Add 9 to each each side

2x^2-4x-9+9=29+9

2x^2-4x=38

Divide by 2

2/2x^2-4/2x=38/8

x^2 -2x =19

Complete the square

x^2 -2x + (-2/2)^2 = 19 +(-2/2)^2

x^2 -2x +1 = 19+1

(x-1)^1=2 = 20

Take the square root of each side

sqrt((x-1)^2) = ±sqrt(20)

x-1 =  ±sqrt(20)

Add 1 to each side

x-1+1 = 1  ±sqrt(20)

x = 1 ±sqrt(20)

Simplifying the square root of 20

x = 1  ±sqrt(4)sqrt(5)

x = 1  ±2sqrt(5)

3 0
4 years ago
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