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3 years ago

Describe 2 applications of surface tension

1 answer:

8 0

Application of surface tension:
1) A needle placed on water can be made to float due to the surface tension of water.
2) Mosquito eggs can float on water because of its surface tension.
3) Toothpaste contains soap, which reduce the surface tension and helps it spread freely in the mouth.

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State in which atoms or molecules are very close together and are regularly arranged

umka21 [38]

Solid, because the atoms maintain their form and do not take the shape of their container. The particles share tight, close bonds due to this set shape

7 0

3 years ago

Read 2 more answers

A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits

Westkost [7]

Answer:

(a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Explanation:

Given that,

Mass of neutron $M_{n}= 13M_{s}$

Density of neutron $\rho=4.8\times10^{17}\ kg/m^3$

(a). We need to calculate the rotational inertia

Using formula of rotational inertia for sphere

$I=\dfrac{2}{5}MR^2$ ...(I)

We know that,

$\rho=\dfrac{M}{V}$

Put the value of volume

$\rho=\dfrac{3M_{n}}{4\pi R^3}$

$R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value of R in equation (I)

$I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value into the formula

$I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}$

$I=5.72\times10^{39}\ kg m^2$

The rotational inertia is $5.72\times10^{39}\ kg m^2$ .

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

$\tau=I\times \alpha$

Put the value into the formula

$\tau=5.72\times10^{39}\times5.6\times10^{-5}$

$\tau=3.20\times10^{35}\ N-m$

The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Hence, (a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

4 0

3 years ago

If you do 200 joules of work using a force of 50 newtons, over what distance was the force applied ?

harina [27]

By using the formula for work, we can derive the force

W = Fd
F= $\frac{W}{d} = \frac{200}{50} = 4 N$

If you found that helpful, please rate this as "Brainiest"

5 0

3 years ago

Read 2 more answers

If a Cu 2+ ion that is initially at rest accelerates through a potential difference of 12 V without friction, how much kinetic e

IgorC [24]

Answer:

23,8eV

Explanation:

A=Uq=12 (V)* 2* 1,6*10^-19 (C)=3,84*10^-18 (J)= 23,8 (eV)

8 0

4 years ago

a car traveling at 7.0 m/s accelerates uni formally at 2.5 m/s^2 to reach a speed of 12.0 m/s how long does it take for the acce

Ronch [10]

The problem wants to compute how long does it take for the acceleration to occur if a car travelling at 7m/s accelerates uniformally at 2.5 m/s^2 to reach a speed of 12 m/s and base on that, the time duration would be 2 seconds. I hope this would help

3 0

3 years ago