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defon
2 years ago
12

What would be the answer for this and how?

Physics
1 answer:
Veronika [31]2 years ago
7 0

Answer:

B. 6 cm

Explanation:

First, we calculate the spring constant of a single spring:

k = \frac{F}{\Delta x}\\

where,

k = spring constant of single spring = ?

F = Force Applied = 10 N

Δx = extension = 4 cm = 0.04 m

Therefore,

k = \frac{10\ N}{0.04\ m}\\k =  250\ N/m\\

Now, the equivalent resistance of two springs connected in parallel, as shown in the diagram, will be:

k_{eq} = k + k\\k_{eq} = 2k = 2(250\ N/m)\\k_{eq} = 500\ N/m\\

For a load of 30 N, applying Hooke's Law:

\Delta x = \frac{F}{k_{eq}}\\\\\Delta x = \frac{30\ N}{500\ N/m}\\\\\Delta x = 0.06\ m = 6\ cm\\

Hence, the correct option is:

<u>B. 6 cm</u>

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During maneuvers preceding the Battle of Jutland, the British battle cruiser Lion moved as follows (in nautical miles): 1.2 mile
lana66690 [7]

Answer:

total distance is 11.3 miles

Explanation:

Given data:

distance to north = 1.2 miles

distance to south at 38 degree east of south = 6.1 miles  

distance to east of north at angle 89 degree = 4 miles  

distance to east of north at angle 31 degree =  6.5 miles

considering each displacement as vector so we have

\begin{pmatrix}0.0\\  1.2\end {pmatrix}   + \begin {pmatrix}3.8\\  -4.8\end{pmatrix} +\begin{pmatrix}4.0\\  0.1\end {pmatrix}+\begin{pmatrix}3.3\\  5.6\end{pmatrix} = \begin{pmatrix}11.1\\  2.1\end{pmatrix}

total distance is \sqrt{11.1^2 + 2.1^2} \approx  11.3

5 0
3 years ago
1)<br> How much time does it take to lift a box using 18.0 J of work and 20.89 Watt of power?
oee [108]

Answer:.

Explanation:

Z

7 0
2 years ago
A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?
olya-2409 [2.1K]

Answer:

First of all the formula is F= uR,( force= static friction× reaction)

mass= 5+25=30

F= 50

R= mg(30×10)=300

u= ?

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3 0
2 years ago
A 1.00 kg block of ice, at -25.0°C, is warmed by 35 kJ of energy. What is the final temperature of the ice?
ahrayia [7]

Answer:

-8.4°C

Explanation:

From the principle of heat capacity.

The heat sustain by an object is given as;

H = m× c× (T2-T1)

Where H is heat transferred

m is mass of substance

T2-T1 is the temperature change from starting to final temperature T2.

c- is the specific heat capacity of ice .

Note : specific heat capacity is an intrinsic capacity of a substance which is the energy substained on a unit mass of a substance on a unit temperature change.

Hence ; 35= 1× c× ( T2-(-25))

35= c× ( T2+25)

35 =2.108×( T2+25)

( T2+25)= 35/2.108= 16.60°{ approximated to 2 decimal place}

T2= 16.60-25= -8.40°C

C, specific heat capacity of ice is =2.108 kJ/kgK{you can google that}

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