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3 years ago

Which type of correlation is suggested by the scatter plot?

Mathematics

1 answer:

Irina18 [472]3 years ago

5 0

Answer:D no correlation

Step-by-step explanation:because if you were to draw a straight line, it wouldn’t be near all of the lines

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4(x2-5x+3)-2(x2-4x+2

Mademuasel [1]

Answer:

-12x+12

Step-by-step explanation:

8-20x+12-4+8x-4

-12x+12

4 0

4 years ago

A worker drags a box of mass 50 kg across a horizontal floor. The worker attaches a rope to the box and pulls on the rope so tha

Arlecino [84]

Answer:

A) $F=\displaystyle{\frac{m(a+ \mu g)}{\cos(\alpha) -\mu \sin(\alpha)} }$ with $a = \frac{2\Delta x}{t^2}$

B) The magnitude of the pulling force is 24 % of the magnitude of the gravitational force acting on the box

Step-by-step explanation:

A) The forces acting on the box are the pulling force that the worker exerts on the rope, the friction, the normal force, and the gravitational force. See the attached diagram. Since the pulling force on the rope makes an angle with the horizontal, this will have components in the x and y-axis (see diagram).

In the y-axis, the box does not move, therefore:

$\sum_{y} F = 0\\F\sin(\alpha) + N - F_g = 0\\N = F_g - F\sin(\alpha)\\N = mg - F\sin(\alpha)$ (1)

where $\alpha$ is the given angle of the rope with the horizontal.

In the x-axis, the box moves with an acceleration $a$ that can be calculated as a function of the given displacement and time interval as:

$a = \frac{2\Delta x}{t^2}$ and the force equation is:

$\sum_{x} F = ma\\F\cos(\alpha) -f =ma\\F\cos(\alpha) - \mu N = ma$

now substituting $N$ from equation (1):

$F\cos(\alpha) - \mu N = ma\\F\cos(\alpha) - \mu (mg - F\sin(\alpha))=ma\\F\cos(\alpha) - \mu mg -\mu F\sin(\alpha)=ma\\F\cos(\alpha) -\mu F\sin(\alpha)=ma+ \mu mg\\F(\cos(\alpha) -\mu \sin(\alpha))=ma+ \mu mg\\\boxed{F=\frac{m(a+ \mu g)}{\cos(\alpha) -\mu \sin(\alpha)}}$

and putting the expression for the acceleration:

$\boxed{F=\frac{m \frac{2\Delta x}{t^2}+ \mu mg}{\cos(\alpha) -\mu \sin(\alpha)}}$ (2)

which is the requested expression

B) Substituting the values in (2) and using $g=9.8\ \rm{ms^{-2}}$ :

$F=\frac{50 \cdot ( 0.762939+ 0.1\cdot \cdot 9.8)}{\cos(36.8^{\circ}) -0.1 \sin(36.8^{\circ})}\\F=\frac{87.147}{0.740829} \\F=11.634\ \rm{N}$

The gravitational force acting on the box is:

$F_g=mg=50\cdot9.8=490\ \rm{N}$

$F/F_g = (117.634/490)\cdot 100 = 24 \%$

Thus, the magnitude of the pulling force is 24 % of the magnitude of the gravitational force acting on the box.

8 0

4 years ago

A dog is tied to a leash on a tree and the leash is 10 meters long. There is a bone 15 meters away but the dog easily gets the b

Alex17521 [72]

Answer:

One way the dog can easily reach the bone is given by the relationship between the dog, the tree, and the bone

The dog can easily reach the bone when the tree is between the the dog and the bone, and the dog was more than 5 meters behind the tree

Therefore the distance the dog can reach in the direction of the bone from its position behind the tree is more than 15 meters and the dog can easily get the bone while the leash is not harmed

Step-by-step explanation:

3 0

3 years ago

Kim's softball team is playing in the championship game. They are losing by a score of 17 to 6. There are 4 innings to go. Kim w

meriva

(how many more needed) divided by (how many innings left)
17-6=11
4 left

11/4=2.75

needs to score 2.75 per inning (even though you can't score 0.75 point)

7 0

3 years ago

Read 2 more answers

John is painting a picture.He has green, red, yellow, purple, orange and blue paint. He wants to use four different colors on th

uysha [10]

Answer:

c) 10

Step-by-step explanation:

You do 5 C 3 ( because you are choosing 3 from the remaining 5).

5C3 = 5!/(3!2!) = 10

5 0

3 years ago

Read 2 more answers