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Dominik [7]
2 years ago
9

An experiment is done on three tomato plants over a 50 day period to test the following hypothesis: If either fertilizer or comp

ost is used on plants, then a plant that gets fertilizer will grow the most.
The same amount of water and light were applied to each tomato plant. Pot A contained no fertilizer or compost, Pot B contained fertilizer, and Pot C contained compost. Which pot is the control?
Biology
1 answer:
olchik [2.2K]2 years ago
3 0

Pot A that contained no fertilizer or compost will serve as a control in this experiment.

<h3>What is Fertilizer?</h3>

Fertilizer may be defined as any chemical or natural substance which is added to the soil with the intention to enhance the soil productivity.

Pot B contained fertilizer, while pot C contained compost, they will definitely grow more than pot A, but pot A serve as a control for this experiment because it does not contain any added resources into it. Hence, it grows naturally.

Thus, it is well described above.

To learn more about Fertilizers, refer to the link:

brainly.com/question/15854400

#SPJ1

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Name the three types of RNA &amp; list their roles in making proteins
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Which is a potential complication of a low pressure in the endotracheal tube cuff? aspiration pneumonia pressure necrosis trache
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4 0
3 years ago
A man is brachydactylous (very short fingers; rare autosomal dominant), and his wife is not. Both can taste the chemical phenylt
netineya [11]

Answer:

The correct answer is -

A) BbTt x bbTt

B) .5^4 or 1/16 or 0.0625

Explanation:

As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.

For Branchydactylus and For tasting :  man and women will be heterogeneous.

Hence,

The Genotype of man = BbTt

The Genotype of wife = bbTt

b. Answer = 0.0625

For Branchydactylus:

Bb X bb

Possible genotypes:

B b

b Bb( Brachydactylus) bb(normal)

b Bb (Brachydactylus) bb (normal)

The probability of a single child being Branchydactylus = 2/4 = 0.5

So,  Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625

3 0
2 years ago
Is it enough for a female to have 1 dominant gene, or do both genes have to be dominant for her to have a disease (for example i
Free_Kalibri [48]

Answer:

In this case most diseases are recessive, but If there is even one dominant allele then it will show over

Explanation:

hope it helps

4 0
2 years ago
Read 2 more answers
........... ........... .................... ........... .......... ............ ............ .............. ............. .....
Vsevolod [243]
This Does not look like a qustion may you please take it down

4 0
3 years ago
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