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strojnjashka [21]
3 years ago
12

897-113×2:2+113A) 888B) 987C) 898D) 1694E) 897​

Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

d it is what it is my man's

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Find the measure of &lt;2!<br> Answer fast pls, 15 pts! &lt;3
Gala2k [10]

Answer:

65

Step-by-step explanation:

180-115=65

It needs to be a total of 180 so just do what I did :)

6 0
2 years ago
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How do I find the area of this shape
vazorg [7]
There's two ways, you can either multiply 11 and 7 to get 77 and then divide by 2, OR, you can divide 11 by 2 and get 5.5 and multiply that by 7, hope this makes sense, if you don't understand just comment and I'll explain it more :)
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A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount x (in dollars) the rest
Simora [160]

Answer:

answer is $819

Step-by-step explanation:

I did 1073+1108+x/3=1000 Let me know if this is wrong please !

7 0
2 years ago
Show all work please will give brainliest answer❕❗️❕❗️❕❗️❕❗️❕David drops a ball from a bridge at an initial height of 100 meters
Inessa [10]
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.

Tell me if you need any clarification

PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds

Tell me if you need any clarification
3 0
2 years ago
Look at the figure shown below:
boyakko [2]

These are the steps, with their explanations and conclusions:


1) Draw two triangles: ΔRSP and ΔQSP.


2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).


3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.


4) The segment SP is common to both ΔRSP and Δ QSP.


5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.


Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q


6 0
3 years ago
Read 2 more answers
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