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Murljashka [212]
3 years ago
11

The diagram represents a difference of squares.

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0
The factors are
(m-6)(m+6)

Explanation:
Group the first two terms and factor out the common factor:
i.e m(m-6)
Repeat the procedure for terms 3 and 4.
6(m-6)

Regrouping:
m(m-6)+6(m-6)

On factoring out (m-6), we get:
(m-6)(m+6)
Naily [24]3 years ago
8 0

Answer: The answer is D. (m – 6)(m + 6).

Step-by-step explanation:

This is 100% correct for the online course edge.nuity.

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It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele
kow [346]

Answer:

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

Step-by-step explanation:

1) Data given and notation      

\bar X=23500 represent the sample mean  

s=3900 represent the sample standard deviation      

n=100 sample size      

\mu_o =2000 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:      

Null hypothesis:\mu \leq 2000      

Alternative hypothesis:\mu > 2000      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=100-1=99  

Since is a one-side upper test the p value would be:      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

8 0
3 years ago
Find the area of an equilateral triangle (regular 3-gon) with 6-inch sides. Round your answer to the nearest hundredth.
Rainbow [258]
Area=9ROOT3 inches
Anyway wanna talk?!

7 0
3 years ago
Madi has 5 apples and 15 oranges. what is a true statement
AlexFokin [52]

Answer:

The true statement is that the answer is 75

Step-by-step explanation:

7 0
3 years ago
Mr. Barnett’s test is normally distributed with a mean of 65 with a standard deviation of five points what is the probability th
uranmaximum [27]

Answer: 2.5%

Step-by-step explanation:

Mean score = 65

Standard deviation = 5

Score (x) = >75

Z-score = [(score - mean) ÷ standard deviation]

Z - score = [(75 - 65) ÷ 5]

Z - score = 10 ÷ 5 = 2

P(score higher than 75) = 100 - 95 = 5/2 = 2.5%

4 0
3 years ago
Hi! I have a math question. This is a two part problem.
Mumz [18]

Answer:

Blair chosen to purchase shirt from company B. Given:

Each shirt costs 3.10$

Shipping cost is 4% (0.04) of total order.

=>Total cost without shipping: 150 x 3.10 = 465$

=> Total cost with 4% of shipping: 465 + 465 x 0.04 = 483.6$

=> Total cost Blair paid for one shirt: C = 483.6/150 = 3.22$

The markup is 75% of original cost:

=> Blair can multiply the total cost for one shirt by 0.75

Blair will sell shirt with price which is equal to the sum of total cost for one shirt and markup:

=> P = 3.22 + 3.22 x 0.75 = 5.64$

Hope this helps!

:)

5 0
3 years ago
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