Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .
Rule: (x, y)→(x + 8, y + 1 )
J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)
J’ (6,3)
K’ (5,-3)
L’ (9,-1)
Hope this helps!
Answer:
V ≈ 527.79
Step-by-step explanation:
Formula is V= πr2h
therefore
V = π * 4 * 2 * 10.5
V = π * 8 * 10.5
V ≈ 527.79
2.8
-14x+28=-4x
10x=28
X=2.8
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