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2 years ago

The bearing of point Y from point X is 070°.

Mathematics

1 answer:

Shkiper50 [21]2 years ago

6 0

The bearing of point X from point Z is 285°

<h3>Calculating bearings </h3>

From the question, we are to determine the bearing of point X from point Z.

Consider the diagram attached

The bearing of point X from point Z is the measure of the angle from the North of Z in the clockwise direction to the line that goes to X.

That is,

The bearing of point X from point Z = 270° + 15°

The bearing of point X from point Z = 285°

Hence, the bearing of point X from point Z is 285°

Learn more on Calculating bearings here: brainly.com/question/22719608

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Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG

qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

Opposite sides are equal and parallel.
Opposite angles are equal to each other.
Consecutive angles are supplementary
The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

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3 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

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$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

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$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

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$\implies S(t)=100P-(100P-25)e^{-100t}$

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has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

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