Ask question

Ask question

All categories

3 years ago

10

Can you help me on these math problems?

1 answer:

densk [106]3 years ago

8 0

I cannot help you unless I know what ones you need help on

You might be interested in

If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?

Dmitrij [34]

A is the point (-4, 1)

i) reflection over the y-axis projects a point (a, b) to (-a, b):

(-4, 1) is projected to (4, 1),

ii) reflection over the x axis projects a point (a, b) to (a, -b):

(4, 1) is projected to (4, -1),

iii) rotation 180 degrees: projects (a, b) to (-a, -b):

so (4, -1) is projected to (-4, 1)

Answer: A'(-4, 1)

8 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ASHA 777 [7]

The area of the given figure is 576 cm sq.

The perimeter of the given figure is 96 cm.

Step-by-step explanation:

The shape consists of one semicircle and one square which is cut by a semicircle.

<u>To find Area:</u>

Find the area of semicircle= (πr^2)/2

where r is the radius= diameter/2= 24/2= 12 cm

Area of semicircle= π(12)(12)/2= 144π/2= 72π cm sq.

Find the area of square= a^2

where a is the side of square, a=24 cm.

Area of the square= 24*24= 576 cm sq.

To find the total area of the given figure,

Area of the figure= Area of semicircle+(area of square- area of semicircle)

= 72π+576-72π =576 cm sq.

<u>To find perimeter:</u>

Perimeter of semicircle= (2πr)/2

= (2*12*π)/2= 12π cm

Perimeter of square= 4a =4*24 =96 cm

Perimeter of the given figure= perimeter of semicircle+(perimeter of square- perimeter of semicircle)

= 12π+96+12π =96 cm.

4 0

3 years ago

The sixth grade is raising money for a camping trip that costs $2,500. So far they have raised 70% of the cost. How much have th

ratelena [41]

Answer:

Step-by-step explanation:

They have raised $1,750 so far. 70% of $2,500 is $1,750

7 0

3 years ago

Read 2 more answers

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

has roots $x_1,\ x_2$ , then you have the following factorization:

$p(x) = (x-x_1)(x-x_2)$

In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

$x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})$

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

7 0

4 years ago

Jan made 17 baskets out of 25 shots she took. What was the percent of baskets she made?

scoundrel [369]

Since 100 is 25*4. Then you would multiply 17 by 4. To get your answer. 68%

Hope this helps!

4 0

3 years ago

Read 2 more answers