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Charra [1.4K]
2 years ago
10

El acento está en la ​

Mathematics
1 answer:
Nastasia [14]2 years ago
5 0

Answer:

el acento es donde está las tildes

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The area of a rectangular field is 5695 m².
denpristay [2]

Answer:

85 m

Step-by-step explanation:

5696/67=85

3 0
2 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
A subway train arrives every 10 minutes during rush hour. We are interested in the length of time a commuter must wait for a tra
Umnica [9.8K]

Answer:

A subway train arrives every 10 minutes during rush hour. We are interested in the length of time a commuter must wait for a train to arrive. The time follows a uniform distribution. Find u, which is the average length of time a commuter must wait for a train to arrive. Round to one decimal place. = 3

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3 years ago
Factor out the greatest common factor<br> 20x^4 + 15x^2 - 10x
aleksandr82 [10.1K]
5x(4x^3 + 3x - 2)

There’s a 5 and a x common.
3 0
2 years ago
COMPRÉ 30 LIBROS A 40 BS CADA UNO ; VENDÍ UNOS CUANTOS A 360 BS, A 36 BS CADA UNO. ¿ EN CUANTO DEBO VENDER CADA UNO DE LOS RESTA
Ksenya-84 [330]

Answer:

28BS

Step-by-step explanation:

Compré 30 libros a 40 bs cada uno;

Precio de costo = 30 × 40BS

= 1200 BS

Vendí unos pocos a 360 Bs, a 36 Bs cada uno.

Número de libros vendidos = 360 BS / 36 BS

= 10 libros

Número de libros restantes = 40 BS - 10 BS

= 30 BS

¿Cuánto debo vender cada uno de los libros restantes para no perder ni ganar nada?

Para no ganar ni perder nada, la cantidad total que queda para vender los libros =

1200BS - 360 BS = 840 BS

La cantidad para vender cada uno de los libros restantes sin ganar ni perder nada se calcula como:

840BS / Número de libros restantes

= 840BS / 30BS

= 28BS

8 0
2 years ago
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