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2 years ago

Math problem pls help me

Mathematics

1 answer:

Bumek [7]2 years ago

8 0

9514 1404 393

Answer:

A'(-2, -1), B'(-1, 3), C'(-3, -5), D'(1, 2)

Step-by-step explanation:

Rotation 270° CCW about the origin is accomplished by the transformation ...

(x, y) ⇒ (y, -x)

The rotated point coordinates are shown above and on the graph below.

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a strip of paper is 9/10 of an inch long. you need to cut the paper into 3/12 inch pieces. how many pieces will you be able to c

e-lub [12.9K]

We have to divide 9/10 by 3/12.

if we divide by a fraction, we can instead multiply by it's inverse:

$\frac{9}{12}/ \frac{3}{12} = \frac{9}{12} * \frac{12}{3}$

so now we count:

$\frac{9}{12} * \frac{12}{3} =\frac{9}{1} * \frac{1}{3}=3$

so we can cut exactly 3 pieces!

5 0

3 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0

3 years ago

Please help!!

postnew [5]

$2 \frac{5}{8} \div 2 \frac{1}{2}$
Change the mixed fractions to improper fractions.
To do this, multiply the whole number part by the denominator. Add that to the numerator. Then write the result on top of the denominator.

You would now have:
$\frac{21}{8} \div \frac{5}{2}$
Change the division sign to a multiplication sign by turning the second fraction upside down.
That is,
$\frac{21}{8} \times \frac{2}{5}$

The answer is:
$\frac{42}{40}$

This can be simplified to:
$\frac{21}{20}$

8 0

3 years ago

During the first part of a hike, Andre drank 1.5 liters of the water he brought. If this is 50% of the water he brought, how muc

ira [324]

Answer:

50/100 x X = 1.5

x 100 x100

50x = 150

÷50 ÷50

X = 3

X = 3 liters I am pretty sure

5 0

3 years ago

In the 7th grade, 132 students take Spanish as an elective. If there are 330 seventh graders, what percent of

klasskru [66]

Answer:

Step-by-step explanation: 40% 132/330=0.4 and 0.4 as a percent is 40%

8 0

2 years ago

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