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emmainna [20.7K]
1 year ago
14

What is the greatest common factor of 253 and 345?

Mathematics
2 answers:
Vilka [71]1 year ago
8 0
The greatest common factor of 253 & 345 is 23
dlinn [17]1 year ago
4 0

Answer:

23

Step-by-step explanation:

To find the Greatest Common Factor, or GCF, we need to factor the first 2 numbers and then find the greatest number that is both present in the prime factorization of both numbers.

253 = 1 * 11 * 23

345 = 3 * 5 * 23

Since 23 is both present in both numbers and is the greatest, the GCF of 253 and 345 is 23.

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Gennadij [26K]
Y = -3x + 7

good luck!
5 0
2 years ago
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This was due yesterday please help​
Marianna [84]

Answer: 2.1925153x10 to the 3rd

Step-by-step explanation: hope it helps

3 0
2 years ago
Please help ASAP!!!!!!!!
JulijaS [17]

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Step-by-step explanation:

When numbers are considered, their position or place value matters a lot.

When a decimal number is written, moving left from the decimal point the place value increases ten times and while moving to the right the place value decreases 10 times.

Given two numbers are:

50.8 and 18.35

In order to compare the 5 in both numbers we have to find the place value of 55 in both numbers.

So,

<u>In 50.8:</u>

The place value of 5 in 50.8 is: 50

<u>In 18.35:</u>

The place value of 5 will be: 5/100

To compare the values, we will divide the larger place value by smaller place value

=\frac{50}{\frac{5}{100}}\\\\=\frac{50*100}{5}\\\\= \frac{5000}{5}\\\\=1000\ times

Hence,

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Keywords: Place value, decimals

Learn more about place values at:

  • brainly.com/question/10402163
  • brainly.com/question/10414011

#LearnwithBrainly

4 0
3 years ago
A map distance of 5 inches represents 200 miles of actual distance . Suppose the distance between two cities on the map is 7 inc
Naily [24]
\frac{5}{200} = \frac{7}{x} \\ 5x = 1400 \\ x = 280

therefore, the actual distance is 280 miles. 

(sorry, idk the rule for it)
7 0
2 years ago
Read 2 more answers
Make vthe subjject of the formulaE=mvsquare/ 2<br>find the value of v when m =2 and E=64​
Maksim231197 [3]

E=mv²

divide both sides by m

E/m=v²

square root both sides

v=√E/m

m=2,E=64

v=√64/2

v=9/√2

6 0
3 years ago
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