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emmainna [20.7K]
1 year ago
14

What is the greatest common factor of 253 and 345?

Mathematics
2 answers:
Vilka [71]1 year ago
8 0
The greatest common factor of 253 & 345 is 23
dlinn [17]1 year ago
4 0

Answer:

23

Step-by-step explanation:

To find the Greatest Common Factor, or GCF, we need to factor the first 2 numbers and then find the greatest number that is both present in the prime factorization of both numbers.

253 = 1 * 11 * 23

345 = 3 * 5 * 23

Since 23 is both present in both numbers and is the greatest, the GCF of 253 and 345 is 23.

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50 POINTS please help me I really need it
Mars2501 [29]

A Domain is the lowest and highest x value (-5,-2) is how it is formatted this means -5 to -2

Range is the lowest to highest Y value so (-3,3)

(-5,-2) - domain

(-3,3) - range

B Intercept are when the line crosses the acis labeled x so

(-2,0) and (2,0)

C F(1) means what is x when y is equal to 1 so we must estimate this

(-1,1) and (1.5,1)

D f(x) = -3 is when y is -3 so we look at the graph to see

-5 and 4 are the values for x

E f(x) < 0 means when y is above the x axis

This is between the x values of -2 and 2 or (-2,2)


7 0
3 years ago
The expression f(x) = 12(1.035)* models the monthly growth of membership in the new drama club at a school. According to the fun
olga nikolaevna [1]

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

y=a(1+r)^{x}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>x</em> = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

f(x) = 12\cdot(1.035)^{x}

Comparing this function with the exponential growth function:

a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}

Then value of <em>r</em> is 0.035 or 3.5%.

Thus, the monthly growth rate is 3.5%.

7 0
3 years ago
If you get this right I will mark you as a brainliest
lara [203]
Is it D. 58? or B.91?
4 0
3 years ago
One gallon of gasoline in buffalo, New York costs $2.29. In Toronto, Canada, one liter of gas costs $0.91. There are 3.8 liters
Solnce55 [7]

<u>Answer:</u>

The cost of one gallon of gas in Toronto, Canada is $3.458.

<u>Solution: </u>

Given, One gallon of gasoline in buffalo, New York costs $2.29.  

In Toronto, Canada, one liter of gas costs $0.91.  

There are 3.8 liters in one gallon.  

We have to find how much does one gallon of gas cost in Toronto?

Now, cost of one gallon of gas in Toronto = cost of one litre of gas in Toronto x 3.8 liters for 1 gallon.

Cost of one gallon of gas = 0.91 x 3.8 = 3.458

Hence, the cost of one gallon of gas in Toronto, Canada is $3.458.

3 0
3 years ago
What is the value of the 3 in 63?
Rina8888 [55]

Answer:

ones

Step-by-step explanation:

63

6=60

3=3

so it is in the ones place

6 0
2 years ago
Read 2 more answers
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