Question

Given: ABCD trapezoid BC=1.2m, AD=1.8m AB=1.5m, CD=1.2m AB∩CD=K Find: BK and CK

Answer 1

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

$AD\parallelBC$

$\angle KBC=\angle KAD$              (Corresponding angles)

$\angle KCB=\angle KDA$             (Corresponding angles)

By AA rule of similarity

$\triangle KBC\sim \triangle KAD$

Corresponding sides of similar triangles are proportional.

$\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}$

$\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}$

$\frac{x}{x+1.5}=\frac{1.2}{1.8}$

$\frac{x}{x+1.5}=\frac{2}{3}$

$3x=2x+3$

$x=3$

The length of BK is 3 m.

$\frac{y}{y+1.2}=\frac{1.2}{1.8}$

$\frac{y}{y+1.2}=\frac{2}{3}$

$3y=2y+2.4$

$y=2.4$

The length of CK is 2.4 m.

Answer 2

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

AD\parallelBC

\angle KBC=\angle KAD              (Corresponding angles)

\angle KCB=\angle KDA             (Corresponding angles)

By AA rule of similarity

\triangle KBC\sim \triangle KAD

Corresponding sides of similar triangles are proportional.

\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}

\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{2}{3}

3x=2x+3

x=3

The length of BK is 3 m.

\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{y}{y+1.2}=\frac{2}{3}

3y=2y+2.4

y=2.4

The length of CK is 2.4 m.