Solve the equation below.
2 answers:
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We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
Answer:
Larger number = 32
Step-by-step explanation:
Smaller number = x
Larger number = y
y - x = 8 -----------(I)
3y = 4x ---------------(II)
3y/4 = x
Plug in x = 3y/4 in equation (I)
y = 8*4
y = 32
Plug in y = 32 in equation (II)
3y = 4x
3*32 = 4x
4x = 3*32
x =
x = 3 *8
x = 24
70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.
Step-by-step explanation:
Given,
56 bottles hold 20 ounces each.
Total amount 56 bottles hold= 56x20
Total amount hold by 56 bottles= 1120 ounces
Let the number of 16 ounces bottles be = x
Total amount hold by x bottles = 16x
According to the given statement both amounts are same;
70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.
Keywords: Division, Multiplication
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