<u>Answer:</u>
square units
<u>Step-by-step explanation:</u>
Knowing the function and that the triangle is formed by both the x and y-axis, you already have the triangle's height, which is 10 (the y-intercept of the functon) To find the base length, all you have to do is find the x-intercept. To do that, simply:
Set function equal to 0 and solve for x:
f(x) = 10 - 
x
0 = 10 - x
x = 10
x = 
This means that the base length of the triangle is also . Now that you have the height and base length, you can
Plug values into the formula for the area of a triangle:
The area of a triangle is 
× height × base
Height = 10, base =
Area = × 10 ×
Area = 5 ×
Area =
Answer:
B. 3x -2y = 10
Step-by-step explanation:
The given line rises three units for each two units of run to the right. Hence its slope is 3/2. A parallel line will also have a slope of 3/2.
Of the equations we can see, selection B has a slope of 3/2. It can be rewritten in slope-intercept form as ...
3x -10 = 2y . . . . . add 2y-10 to isolate the y-term; next divide by 2.
y = 3/2x -5 . . . . . the coefficient of x is the slope
Answer:
161y - 45
Step-by-step explanation:
Given the quadratic equation:
Using the general solution for quadratic equations:
From the problem, we identify:
Then:
And the solution set is:
![\lbrack\frac{-5-3\sqrt{5}}{2},\frac{-5+3\sqrt{5}}{2}]](https://tex.z-dn.net/?f=%5Clbrack%5Cfrac%7B-5-3%5Csqrt%7B5%7D%7D%7B2%7D%2C%5Cfrac%7B-5%2B3%5Csqrt%7B5%7D%7D%7B2%7D%5D)
