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Ann [662]
3 years ago
10

The area of a rectangle a=1(w) is represented by the expression 24x6y15. If the width of the rectangle is 2x3y9, what is the l

ength of the rectangle
Mathematics
1 answer:
natulia [17]3 years ago
8 0

Answer:

Length of rectangle is: Length=12x^3y^6

Step-by-step explanation:

The area of rectangle = 24x^6y^{15}

Width of rectangle = 2x^3y^9

We need to find length of rectangle

The formula used is: Area=Length\times Width

Putting values and finding length

Area=Length\times Width\\24x^6y^{15}=Length\times 2x^3y^9\\Length=\frac{24x^6y^{15}}{2x^3y^9} \\Length=12x^{6-3}y^{15-9}\\Length=12x^3y^6

So, Length of rectangle is: Length=12x^3y^6

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Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

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To find the point of intersection, we need to solve the system of equations  and the result will be the point of intersection (x,y)

x-2y+1=0\\x= 2y-1

Now we substitute x in the second equation:

2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7

Now we substitute y in our first equation.

x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7.

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

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We are going to follow the same procedure:

x-2y+11=0\\x=2y-11

-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0
2 years ago
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solong [7]
24 + 4(3 + 1)
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