Question

Evaluate: 10 Σ¹0 4(1)n-1 = [?] Round to the nearest hundredth. Enter

Answer 1

Answer:

Using the formula of geometric progression, we get 5.33 after rounding off to the nearest hundredth.

Step-by-step explanation:

Concept: Given expression is means that $4(\frac{1}{4} )^{n-1}$ is a series that starts from n=1 and ends at n=10. This will make a geometric progression. Use the formula of geometric progression to find the answer.

$4(\frac{1}{4})^{0} + 4(\frac{1}{4})^{1} + 4(\frac{1}{4})^{2} +...+ 4(\frac{1}{4})^{10}\\4\frac{-(\frac{1}{4} )^{11} +1}{-\frac{1}{4} +1} \\4\frac{1}{\frac{3}{4} } \\\frac{16}{3} \\5.33333333\\5.33$

The answer, to the nearest hundredth is 5.33

For more explanation, refer the following link

brainly.com/question/27959890

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