2 years ago

Help ASAP! Please this is hard!

Mathematics

1 answer:

Dafna1 [17]2 years ago

3 0

No
yes
yes
yes
no
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DochEvi [55]

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Trava [24]

Answer: $12k^5+24k^4+30k^3$

Step-by-step explanation:

Given : The height of the rectangle = $6k^3$

The width of the rectangle = $2k^2+4k+5$

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Therefore , the area of triangle in terms of polynomial will be :

$6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3$

Hence, the area of the entire rectangle = $12k^5+24k^4+30k^3$

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3 years ago

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sweet-ann [11.9K]

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8/21

Step-by-step explanation:

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