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Vera_Pavlovna [14]
4 years ago
5

Write the equation of the line that has a slope of -2 and goes through the point (-3,4).

Mathematics
2 answers:
liubo4ka [24]4 years ago
4 0

<u>SOLUTION:</u>

General Equation: y = mx + b

.

Substitute slope = -2 into the equation:

y = -2x + b

.

Find the y-intercept:

4 = -2(-3) + b

4 = 6 + b

b = -2

.

Substitute b = -2 into the equation:

y = -2x - 2

.

Answer: y = -2x - 2

belka [17]4 years ago
3 0

We are given

slope=m=-2

point is (-3,4)

so, we can use point slope form of line

y-y_1=m(x-x_1)

Here ,

x_1=-3, y_1=4

now, we can plug values in formula

and we get

y-4=-2(x+3)

now, we can solve for y

y-4=-2x-6

y=-2x-2..............Answer

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a) P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928

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The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

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X \sim Binom(n=100, p=0.127)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

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a. What is the probability that you count exactly 10 in poverty?

For this case we want this probability P(X=10)

P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928

b. What is the probability that you count 10 or less in poverty?  .2614

For this case we want this probability P(X=\leq10)

P(X\leq10)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)

And we can find the individual probabilities like this:

P(X=0)=(100C0)(0.127)^{0} (1-0.127)^{100-0}=1.263x10^{-6}

P(X=1)=(100C1)(0.127)^{1} (1-0.127)^{100-1}=1.837x10^{-5}

P(X=2)=(100C2)(0.127)^{2} (1-0.127)^{100-2}=0.000132

P(X=3)=(100C3)(0.127)^{3} (1-0.127)^{100-3}=0.000629

P(X=4)=(100C4)(0.127)^{4} (1-0.127)^{100-4}=0.00222

P(X=5)=(100C5)(0.127)^{5} (1-0.127)^{100-5}=0.00620

P(X=6)=(100C6)(0.127)^{6} (1-0.127)^{100-6}=0.0143

P(X=7)=(100C7)(0.127)^{7} (1-0.127)^{100-7}=0.0279

P(X=8)=(100C8)(0.127)^{8} (1-0.127)^{100-8}=0.0471

P(X=9)=(100C9)(0.127)^{9} (1-0.127)^{100-9}=0.0701

P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928

And then repplacing we got:

P(X \leq 10) = 0.2614

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For this case we need after 7 people , 1 in poverty so we can find this probability like this:

(1-0.127)^7 (0.127) =0.0491

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