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4 years ago

Quick math problem, need help ASAP!

Mathematics

1 answer:

adelina 88 [10]4 years ago

5 0

Answer:

I think it's systamatic. I'm not completely sure sorry

Step-by-step explanation:

You might be interested in

For questions 4–5, simplify the expression.

Alex17521 [72]

1. $\mathrm{Group\:like\:terms} \ \textgreater \ 24h-10h+3d+8d$

$\mathrm{Add\:similar\:elements:}\:24h-10h=14h \ \textgreater \ 14h+3d+8d$

$\mathrm{Add\:similar\:elements:}\:3d+8d=11d \ \textgreater \ 14h+11d$

2. $\mathrm{Group\:like\:terms} \ \textgreater \ 12s+4s-2+4$

$\mathrm{Add\:similar\:elements:}\:12s+4s=16s \ \textgreater \ 16s-2+4$

$\mathrm{Add/Subtract\:the\:numbers:}\:-2+4=2 \ \textgreater \ 16s+2$

Hope this helps!

4 0

3 years ago

I WILL RATE YOU BRAINLIEST PLEASE HELP!!!!! I tried to put in .7 for the first one but that didn't work

drek231 [11]

The answer is the answer is 0.7 not just .7

4 0

3 years ago

The output y and input x of a device are related by y = x + 1.4x3 . (a) Find the values of the output for steady-state operation

erma4kov [3.2K]

Answer:

a) $y(1) = 2.4$ , $y(2) = 13.2$ , b) $y(x) = 2.4 + 5.2\cdot (x-1)$ , $y(1) = 2.4$ , $y(2) = 7.6$

Step-by-step explanation:

a) The values of the output for steady-state operation are:

$y(1) = 1 + 1.4\cdot (1)^{3}$

$y(1) = 2.4$

$y(2) = 2 + 1.4\cdot (2)^{3}$

$y(2) = 13.2$

b) The formula for linearization is:

$y(x) = y(1) +\frac{dy}{dx}|_{x = 1} \cdot (x-1)$

The first derivative of the formula evaluated at x = 1 is:

$\frac{dy}{dx}|_{x=1} = 1 + 4.2\cdot (1)^{2}$

$\frac{dy}{dx}|_{x=1} = 5.2$

The linearized model is:

$y(x) = 2.4 + 5.2\cdot (x-1)$

The output at x = 2 is presented below:

$y(2) = 2.4 + 5.2\cdot (2-1)$

$y(2) = 7.6$

Linearized model offers reasonable approximations for small intervals.

5 0

3 years ago

Chai Hu deposited $5500 in a savings account earning 6% interest compound quarterly if he makes no other deposits or withdrawals

Arada [10]

Answer:

5,477.63

Step-by-step explanation:

First, convert R percent to r a decimal

r = R/100

r = 6%/100

r = 0.06 per year,

Then, solve our equation for P

P = A / (1 + r/n)nt

P = 5,500.00 / (1 + 0.06/4)(4)(0.068448)

P = 5,500.00 / (1 + 0.015)(0.273792)

P = $ 5,477.63

Summary:

The principal investment required to get

a total amount of $ 5,500.00

from compound interest at a rate of 6% per year

compounded 4 times per year

over 0.068448 years

is $ 5,477.63.

** i got this from calculator soup

8 0

3 years ago

The marketing director of a large department store wants to estimate the average number of customers who enter the store every f

Dahasolnce [82]

Answer:

$36.5674\leq x'\leq61.4326$

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

$x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }$

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, $\alpha$ is equal to 0.05 (it is calculated as: 1 - 0.95) and $t_{\alpha /2}$ is the t value with n-1 degrees of freedom that let a probability of $\alpha/2$ on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and $t_{\alpha /2}$ by 2.2621 we get:

$49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326$

Finally, the interval values that she get is:

$36.5674\leq x'\leq61.4326$

8 0

3 years ago