Question

A rectangular dartboard has an area of 648 square centimeters. The triangular part of the dartboard has an area of 162 square centimeters. A dart is randomly thrown at the dartboard.
Assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle?

To the nearest whole percent, the probability is

Answer 1

Okay, like I explained before:

Divide the area of the triangle by the area of the rectangle and multiply by 100 to get the probability of landing inside the triangle as a percentage...

P%=100(162/648)

P%=25%

Answer 2

   we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

the probability is equal to

P=size of the event space/size of the sample space

In this problem

size of the sample size=area of the rectangular dartboard=$648\ cm^{2}$

size of the event space=area of the triangular part=$162\ cm^{2}$

$P=\frac{162}{648}=0.25$

Convert to percentage

$P=0.25*100=25\%$

therefore

the answer is

$25\%$