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emmainna [20.7K]
3 years ago
14

Company A has 400 employees and Company B has 500 employees. Among these employees, there are 50 married couples, each consistin

g of an employee from A and an employee from B. If 1 employee is to be selected at random from each company, what is the probability that the 2 employees selected will be a married couple?
Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:0,0025

Step-by-step explanation:

P(select a married couple) = P(person selected from Company A is one of the 50 with spouse at Company B) x P(person selected from Company B spouse of person already selected from Company A)

Now you can substitute the respective probabilities .

= (50/400) x (1/500)

= 0,0025

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Answer:  586.59 cubic centimeters .

Step-by-step explanation:

As per given . we have

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⇒Inner radius :r = 0.9 in.  (radius is half of diameter)

= 0.9 x (2.54) = 2.286 cm  [∵ 1 in . = 2.54 cm]

Outer diameter = 2 inches

⇒Outer radius : R = 1 inch  = 2.54 cm

Height : h = 5 feet = 5 x(30.48) = 152.4 cm   [∵  1 foot = 30.48 cm]

The formula to find the volume of a hollow cylinder :

V=\pi(R^2-r^2)h , where R= outer radius , r= inner radius and h= height.

Now , the volume of metal in the conduit :

V=(3.14)(( 2.54)^2-(2.286)^2)(152.4)

V=(3.14)(6.4516-5.225796)(152.4)

V=(3.14)(1.225804)(152.4)

V=586.591342944\approx586.59\ cm^3

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Alona [7]

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<u>Answer:</u>

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