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makvit [3.9K]
3 years ago
11

6(3X-5) -7X=25 Solve X

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

18x-30-7x = 25

11x = 55

x = 55/11

x=5

Brrunno [24]3 years ago
3 0

Answer:

x=5

Step-by-step explanation:

it just is

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the probability is 1

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3 years ago
Solve for F: C=5/9(F-32)<br> please explain process thanks
timama [110]
C=\frac{5}{9}(F-32)\ \ \ \ /\cdot\frac{9}{5}\\\\F-32=\frac{9}{5}C\ \  \ \ /+32\\\\F=\frac{9}{5}C+32\\\\F=\frac{9C}{5}+\frac{160}{5}\\\\F=\frac{9C+160}{5}
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3 years ago
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Y2-x3 when x=2,y=4 x1+x3-y2 when x=3 y=5 x4 divide x3 x=6 please help am bad at this
Katen [24]

Answer:

8 , 5 , 5.785

Step-by-step explanation:

y^2 - x^3

first just plug in the numbers and you get

(4)^2 - (2)^3

Multiply

16-8 and this equals 8

x1 + x^3 - y^2

same pattern plug in the numbers

(3)^(1) + (3)^3 - (5)^2

multiply

3 + 27 - 25

P

E

M

D

Addition

Subtraction so do 3+27 first and you get

30 - 25 = 5

x^4 / x^3 plug it in

(6)^4 / (6)^3

multiply

1269  / 216  

divide this and you get

5.875

8 0
3 years ago
A population p of migrating butterflies changes over time it is represented by the equation p=100,000*4/5 where w is the number
Trava [24]

Given that,

A population p of migrating butterflies changes over time it is represented by the equation

p=100,000\times (\dfrac{4}{5})^w Where w is number of weeks.

To find,

The population after 2 weeks.

Solution,

We have,

p=100,000\times (\dfrac{4}{5})^w

Put w = 2 in the above equation.

p=100,000\times (\dfrac{4}{5})^2\\\\=100,000\times \dfrac{16}{25}\\\\=64000

So, the population after 2 weeks is 64000 .

7 0
3 years ago
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