Question

Please help me with this problem!

Answer 1

Answer:

The choice A ;

$\frac{1}{ {7}^{8} }$

Step-by-step explanation:

$\frac{ {7}^{ - 6} }{ {7}^{2} } = \frac{ {7}^{ - 6 - 2} }{1} = {7}^{ - 8} = \frac{1}{ {7}^{8} } \\ \\ \\ or. \: \frac{ {7}^{ - 6} }{ {7}^{2} } = \frac{1}{ {7}^{ 2 + 6} } = \frac{1}{ {7}^{8} }$

Answer 2

Hii!

Answer:

Step-by-step explanation:

Use the rule of exponents.

If we divide two numbers with the same bases, we subtract the exponents.

7^-6/7^2=7^-6-2=7^-8

Now, if we have a negative exponent, we flip over the number.

7^-8=1/7^8

Great job!

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Hope that this helped.