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Neko [114]
3 years ago
8

A number is totally even if all its digits are even. For instance, the numbers 2022 is totally even. How many four-digit totally

even numbers X are there such that X + 2022 is totally even?
Mathematics
1 answer:
dem82 [27]3 years ago
3 0

Answer:

The units digit of our number should be and can be any of 0, 2, 4, 6  (four opportunities).

The tens  digit of our number should be and can be any of 0, 2, 4, 6  (four opportunities).

The hundreds digit of our number should be and can be any of 0, 2, 4, 6, 8  (five opportunities).

The thousands digit of our number should be and can be any of 2, 4, 6  (three opportunities).

So, there are 4*4*5*3 = 16*15 = 240  such 4-digits totally even numbers, satisfying the condition.     ANSWER

Step-by-step explanation:

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That is sometimes true because there might be more green than red

Step-by-step explanation:

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Decide which shipping box (or combination of boxes) she should use to ship exactly 270 necklaces.
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3 years ago
Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​
pochemuha

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - \frac{b}{a} = \frac{5}{2}

product of roots = \frac{c}{a} = - 3, then

sum of new roots = \frac{1}{\alpha } + \frac{1}{\beta }

= \frac{\beta+\alpha  }{\alpha \beta }

= \frac{\frac{5}{2} }{-3} = - \frac{5}{6}

product of new roots = \frac{1}{\alpha } × \frac{1}{\beta }

= \frac{1}{\alpha\beta  } = - \frac{1}{3}

Hence the required equation is

x² + \frac{5}{6} x - \frac{1}{3} = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

                           

8 0
4 years ago
Please Please Please Please help!!<br><br>#19
photoshop1234 [79]
Im not good with math sry
3 0
4 years ago
Express the product in simplest form.
Dmitry [639]

The product in simplest form is (x - 4)

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{8}{2x+8} \times \frac{x^2-16}{4}

We have to find the product in simplest form

In the given expression,

2x + 8 = 2(x+ 4)

We know that,

a^2-b^2=(a+b)(a-b)

Therefore,

x^2-16 = x^2-4^2 =(x+4)(x-4)

Substitute these in given expression

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4}

Cancel the common factors,

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4} = x - 4

Thus the product in simplest form is (x - 4)

8 0
3 years ago
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