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3 years ago

Who is good at math??

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

B = 26in, c = 40in
a^2 = 26^2 + 40^2
= 2276 (square root it)
a = 2root569 // 47.7in

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1) Para que valores reais de x o ponto P (3x -6, 2x +4) pertence ao 4º quadrante?

skelet666 [1.2K]

Answer:

There are no real values of x for point P to belong to the 4 quadrant

Step-by-step explanation:

<u><em>The question in English is</em></u>

To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?

we know that

A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative

we have the point

P (3x-6, 2x+4)

$3x-6 > 0$ ----> inequality A ( x-coordinate must be positive)

$2x+4 < 0$ ---> inequality B ( y-coordinate must be negative)

Solve Inequality A

$3x-6 > 0$

$3x > 6$

$x > 2$ -----> (2,∞)

Solve Inequality B

$2x+4 < 0$

$2x < -4$

$x < -2$ ----> (-∞,-2)

The solution of the system is

(-∞,-2) ∩ (2,∞)

therefore

The system has no solution

There are no real values of x for point P to belong to the 4 quadrant

3 0

4 years ago

(100 points)

ioda

Answer:

1a. The other addend of 17,300

1b. 17,300 and 11,210

1c. 17,300-11,210

1d. 17,300-11,210= 6090

1e. 6090

2a. The other factor of 954

2b. 954 and 318

2c. 954-318

2d. 954-318= 636

2e. 636

3a. The total amount of fruit Hector bought.

3b. 7 and 24

3c. 7 x 24

3d. 7 x 24 = 168

3e. 168 fruits

6 0

3 years ago

thomas has 4 blocks colored blue,red,green and yellow. How many different ways can he combine them on a shelf?

puteri [66]

Answer: 24

Step-by-step explanation:

Take the factorial of that number.

4! = 4*3*2*1=24

8 0

4 years ago

If a pair of regular dice are tossed once, use the expectation formula to determine the expected sum of the numbers on the upwar

Darya [45]

Answer:

The expected sum of the numbers on the upward faces of the two dice is 7.

Step-by-step explanation:

Consider the provided information.

If two pair of dice tossed the possible out comes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6,6)

Now we need to find the expected sum of the numbers on the upward faces of the two dice.

The expected sums can be:

Sum: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

Prob: 1/36, 2/36, 3/36, 4/36, 5/36, 6/36, 5/36, 4/36, 3/36, 2/36, 1/36

As we know that the expectation of experiment can be calculated as:

$P(S_1)\cdot S_1+P(S_2)\cdot S_2+........+P(S_n)\cdot S_n$

Here S represents the numerical outcomes and P(S) is the respective probability.

Substitute the respective values in the above formula.

$=2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\=\frac{252}{36}\\=7$

Hence, the expected sum of the numbers on the upward faces of the two dice is 7.

8 0

4 years ago

On Monday Mrs. Wise bought 3 lbs of apples at $4 per lb. On Tuesday, apples were on sale for 20% off so she bought another 5 lbs

scZoUnD [109]

OK we have to know how much it costs for 5lbs but if it is still $4 then the answer is $2 on Tuesday!

8 0

3 years ago

Read 2 more answers