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Effectus [21]
2 years ago
5

Calculate the deferred tax liability given the following Items Incurred In 2020 by Company B. Bonuses are tax deductible only in

the year in which they are paid. AccountingIncome $86,000 Deprec1at1on Expense $6,500 Tax Depreciation $4,000 Income Not Recognized InThe Current Period For Tax Purposes $4,700 2019 Bonus Paid in 2020 $2,630 Accrued Bonuses in 2020 $3,500 Tax Rate 28%
Mathematics
1 answer:
german2 years ago
8 0

The deferred tax liability in 2020 for Company B.  would be $372.

<h3>How much of the deferred tax liability is incurred?</h3>

First, we have to find the taxable income:

= $86,000 + $6,500 + $3,500 -$ 4,000 - $4,700 - $2,630

= $84,670

Now, as the accounting income of $86,000 is more than the taxable income of $84,670, there will be a deferred tax liability of:

= ($86,000 - $84,670) * 28%

= $1,330 * 28%

= $372

Therefore, the deferred tax liability in 2020 for Company B.  would be $372.

Read more about deferred tax liability

<em>brainly.com/question/16102904.</em>

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You are given 1000 one dollar bills and 10 envelopes. Put the bills into the envelopes in such a way that someone can ask you fo
taurus [48]

Answer:

We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489

Step-by-step explanation:

  • Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.

This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.

However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.

Observe that:

  1. 1+2+4+8+16+32+64+128+256+489=1000
  2. Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
  3. If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since x-489\leq511, by 2) we know that this would be possible.

4 0
3 years ago
When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?
tatyana61 [14]

Answer:

e=\frac{1}{4} fg

Step-by-step explanation:

Joint variation problem  solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}

The relationship will be:

e=kfg\\e=\frac{1}{4} fg

8 0
3 years ago
Read 2 more answers
the width of a rectangle is 2/3 length, The perimeter of the rectangle is 100 ft. What is the width, in feet, of the rectangle.
lakkis [162]

Answer:

The width would be 20 and the length would be 30

Step-by-step explanation:

7 0
3 years ago
Express the product shown as a fraction in simplest form -3/7 dot -2/3 <br> please help
attashe74 [19]

The answer is \frac{2}{7}.

Multiple numerators by nums, and denoms by denoms.

\\\frac{-3}{7} · \frac{-2}{3}  = \frac{6}{21}

\frac{6}{21} simplified is \frac{2}{7}

Hope this helped and branluest would be appreciated

8 0
3 years ago
Evaluate the expression below.<br> 13-[4•(8-5)+2-9]•2
In-s [12.5K]

Answer:

Step-by-step explanation:

13 - [4 *(8 - 5) + 2 - 9] * 2 =

13 - [ 4 (3) + 2 - 9] * 2 =

13 - [ 12 + 2 - 9] * 2 =

13 - 5 * 2 =

13 - 10 =

3

8 0
3 years ago
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