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Marina86 [1]
1 year ago
9

What is the value marginal product of labor if p = $10, mpl = $25, and apl = 40? multiple choice $400 $10,000 $250 $1,000

Mathematics
1 answer:
ioda1 year ago
3 0

If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250

The marginal product of labor (MPL) is the change in output that results from employing an added unit of labor.

The average product of labor (APL) is the total product of labor divided by the number of units of labor employed.

Here,

P= $10

The marginal product of labor (MPL)= $25

The average product of labor (APL)= $40

The value of marginal product of labor= P × The marginal product of labor (MPL)

The value of marginal product of labor= 10×25=$250

Hence, If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250

Learn more about the value of marginal product of labor here

brainly.com/question/15072173

#SPJ4

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3 years ago
If you can get 4 bottles of fruit juice for 10 dollars how much would 1 bottle cost
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Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam
MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
2 years ago
Last week, steph curry made 56 free throws. if his free throw percentage is 80%, how many free throws did he attempt?
Finger [1]
80% of what is 56
0.80x = 56
x = 56 / 0.80
x = 70....so he attempted 70 free throws
3 0
3 years ago
Read 2 more answers
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