If m AC =86°, find m <AVC

Use the distributive property to simplify the expressions. 1B. -3(9x-q) 2B. 2(12+5p) 3b. -7(-8y+7) 4b. 10(2+7c) 5b. -8(7+11k) 6b

Debora [2.8K]

1B: -3(9x-q)
-27x + 3q

Step 1: Distribute the -3 to the 9x to get -27x.
Step 2: Distribute the -3 to the -q.

2B: 2(12+5p)
24 + 10p

Step 1: Distribute the 2 to the 12 to get 24.
Step 2: Distribute the 2 to the 5p to get 10p.

3B: -7(-8y+7)
56y - 49

Step 1: Distribute the -7 to the -8y to get 56y.
Step 2: Distribute the -7 to the 7 to get -49.

4B: 10(2+7c)
20 + 70c

Step 1: Distribute the 10 to the 2 to get 20.
Step 2: Distribute the 10 to the 7c to get 70c.

5B: -8(7+11k)
-56 - 88k

Step 1: Distribute the -8 to the 7 to get -56.
Step 2: Distribute the -8 to the 11k to get -88k.

6B: -(3-7u)
-1(3-7u)
-3 + 7u

Step 1: Place a 1 after the negative symbol to symbolize -1.
Step 2: Distribute the -1 to the three to get -3.
Step 3: Distribute the -1 to the -7u to get 7u.

7B: -6(5p + s)
-30p - 6s

Step 1: Distribute the -6 to the 5p to get -30p.
Step 2: Distribute the -6 to the s to get -6s.

:) :D

8 0

3 years ago

Can you solve this problem please

Afina-wow [57]

Answer:

k = 11

Step-by-step explanation:

Given the points are collinear then the slopes between consecutive points are equal.

Using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)

m = $\frac{-1-1}{1-5}$ = $\frac{-2}{-4}$ = $\frac{1}{2}$

Repeat with another 2 points and equate to $\frac{1}{2}$

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (k, 4)

m = $\frac{4+1}{k-1}$ , then

$\frac{5}{k-1}$ = $\frac{1}{2}$ ( cross- multiply )

k - 1 = 10 ( add 1 to both sides )

k = 11

6 0

3 years ago

Read 2 more answers

A business owner collected data on the people working for her company. She determined the average number of minutes each employe

Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.

Step-by-step explanation:

The following information is missing

A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.

A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.

The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison?

The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric.

The comparison would be more accurate using the mean and MAD because the median of both data sets is the same.

The comparison using median and IQR is best because one of the graphs is not symmetrical.

The comparison using median and IQR is best because the median is greater than the IQR for both data sets.

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0

3 years ago

Which digit is in the hundred millions place in the number 465,382,109,728

Allisa [31]

3 is in the hundred millions

7 0

3 years ago

Read 2 more answers

6n2 - 5n2 + 7n2 simplify the expresion and show work

olchik [2.2K]

This is just combining like terms.....
6n2 - 5n2 + 7n2
n2 + 7n2
=8n2

4 0

3 years ago