The answer is choice A.
In this problem, we are shrinking the poster by 1/4 of its size.
Which means you need to divide the sides by 4
For width:

For length:
The correct answer to your question is 15 days because if she drinks 1/3 of a can a day it will take 3 days to drink one can. Now multiple the 3 days for one can by the 5 cans and you get 15 days to finish all of the cans.
Answer:
33%
Step-by-step explanation:
Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.
Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.
So we can now equate the parts of the ryegrass in the mixture as:
0.4X + 0.25(100-X) = 30
<=> 0.4X + 25 - 0.25X = 30
<=> 0.15X = 5
<=> X = 5/0.15 = 500/15 = 100/3
So the weight of mixture X as a percentage of the weight of the mixture
= (weight of X/weight of mixture) * 100%
= (100/3)/100 * 100%
= 33%
The point of intersection is the point where lines intersect.
<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Given
<em />
<em> --- the number of lines</em>
<em />
<em> --- no three lines are concurrent</em>
<em />
When no three line are concurrent, it means that no three lines meet at the same point.
<u>So, the sequence of intersection is:</u>
- <em>0 intersection for 1 line</em>
- <em>1 intersection for 2 lines</em>
- <em>3 intersections for 3 lines</em>
- <em>6 intersections for 4 lines</em>
<em />
Following the above sequence, the number of intersections for n lines is:

In this case, 
So, we have:




<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Read more about lines of intersections at:
brainly.com/question/22368617
The difference is 6. Each number increases by 6 in the sequence.
2 + 6 = 8
8 + 6 = 14
14 + 6 = 20
20 + 6 = 26
Etc.
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