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Komok [63]
3 years ago
10

Solve the equation by completing the square. Round to the nearest hundredth if necessary.

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

Answer

2

Step-by-step explanation:

(reorder terms)

<u>2x + 2x</u> = 8

collect like terms

<u>4x=8</u>

divide both sides of the equation

x = 2

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28.26

Step-by-step explanation:

circumference= 2πr or πd (diameter)

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What is the lowest number that can be generated using the digits 2, 8, 5, 3, 3, and 6, in any order?
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Answer:

233568

Step-by-step explanation:

233568

use the smallest digit on the left and write in increasing  order

and the greatest digit on the right as shown.

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Simplify 7.4z - 5 (-1.6z + 2.4) please
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8 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
4 years ago
I don't understand how this would work. Ive tried to figure it out but i don't know.
barxatty [35]
A. Not sure !! .....l.......
8 0
3 years ago
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