The area is that of two 20 yd squares and one 20 yd circle.
.. A = 2*(20 yd)^2 +(π/4)*(20 yd)^2
.. = (2 +π/4)*(400 yd^2)
.. = (800 +100π) yd^2
.. ≈ 1114.16 yd^2
The perimeter is that of a 20 yd circle and 80 yd more.
.. P = π*20 yd + 80 yd
.. ≈ 142.83 yd
Answer:
Step-by-step explanation:
7
To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides

1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself


Simply
3Y+-21=12X
Re-order the terms
-21+3Y=12X
(Solving for Y variable)
Move all terms containing y to the left, all other terms to the right.
Add 21 to each side of the equation
-21+21+3Y=21+12X
Combine like terms: -21+21=0
0+3Y=21+12X
3Y=21+12X
Divide each side by 3
Y=7+4X
Simplifying
Y=7+4x
I hope this helps!! :)