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patriot [66]
3 years ago
11

David's bowling score is 6 less than 2 times Aaron's score. The sum of their scores is 84. Find the score of each student. Use t

he variable a for Aaron's score.
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

Aaron's bowling score is 30

David's bowling score is 54

Step-by-step explanation:

The variable representing Aaron's score is = a

The variable representing David's bowling score = d

The sum of their scores is 84.

= a + d = 84...... Equation 1

David's bowling score is 6 less than 2 times Aaron's score.

d = 2a - 6

Substituting 2a - 6 for d in Equation 1

a + 2a - 6 = 84

3a - 6 = 84

3a = 84 + 6

3a = 90

a = 90/3

a = 30

Hence, Aaron's bowling score is 30

d = 2a - 6

d = 2(30) - 6

d = 60 - 6

d = 54

David's bowling score is 54

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Find the lateral area of a cylinder with the given measurements. Use 3.14 for π and round your answer to the nearest tenth. Heig
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3 years ago
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aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
3 years ago
The number of nails of a given length is normally distributed with a mean length of 5 in and a standard deviation of 0.03 find t
umka2103 [35]

Answer:

19 nails

Step-by-step explanation:

Let's first determine the z-score by using the formula:

z=\frac{x-\mu}{\sigma}

Where x=5.03, μ=5, σ=0.03 and so:

z=\frac{5.03-5}{0.03}=1


We can now use a z-score table to determine that 1.00 is synonymous with 0.8413 meaning 84.13%.  This means that 84.13% of the nails are less than or equal to 5.03 inches long.  Therefore, since we know 100% = 1 in decimals we can determine that the length greater than 5.03 inches is 1-0.8413=0.1587.  This means that 15.87% of the 120 nails are greater than 5.03 inches long.

Finally, we can determine how many nails are greater than 5.03 by determining what is 15.87% of 120 which is:

120 \times 0.1587 \approx 19

And so 19 out of the 120 nails are greater than 5.03 inches long.

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