In the figure, all, and both lines are intersected by transversal & Complete the statements to prove that m≤1 = m25.

Mathematics

1 answer:

m_a_m_a [10]1 year ago

7 0

First blank: Substitution or transitive property of equality

Second blank: Subtraction property of equality

You might be interested in

Use the diagram to determine which statement is true

hichkok12 [17]

A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.

5 0

2 years ago

Read 2 more answers

What can you multiply to give you -42 and add up to 1

yanalaym [24]

-6 + 7 = 1 and -6*7 = -42

So f(x) = (x + 7)(x - 6)

7 0

2 years ago

In the figure, BE||CD. Solve for x. Show your work.

marin [14]

Answer:

Answer is x = 15

Answer is given below with explanations.

Step-by-step explanation:

$in \: the \: figure \: BE || CD \\ by \: thales \: theorem \\ \frac{AE}{ED} = \frac{AB}{BC} \\ on \: substituting \: the \: values \: from \: the \: figure \\ \frac{9}{6} = \frac{x}{10} \\ \frac{3}{2} = \frac{x}{10} \\ x = \frac{3 \times 10}{2} \\ x = \frac{30}{2} \\ x =15 \\$