I think it’s 20d-$12
Hope this helps!
Answer:
y = 4x + 1
Step-by-step explanation:
Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope
Standard form of an equation is y = mx + b
Compare;
mx = 4x
m = 4
Since the slope of the given equation is 4, the required equation must also have a slope of 4
Since we are not given an option, we can assume any equation with a slope of 4
y = 4x + 1 will be parallel to the given equation since they both have the same slope
<em>Note that the equation can be different so far they have the slope of 4</em>
parallel lines have the same exact slope hmmm what's the slope of y = 2/3x-7 anyway? well, low and behold, is already in slope-intercept form, therefore
.
so we're really looking for the equation of a line whose slope is 2/3, and runs through 3, -1.

Answer:
348 m^2
Step-by-step explanation:
The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.
A = LW + bh/2
A = 24 m * 12 m + (24 m)(5 m)/2
A = 288 m^2 + 60 m^2
A = 348 m^2
Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.