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monitta
3 years ago
15

A student ran the 50 yard dash in 5.8 seconds at what speed did the student run in miles per hour round to the nearest 10th

Mathematics
2 answers:
Otrada [13]3 years ago
8 0
The answer is 17.6 miles per hour 
Firdavs [7]3 years ago
6 0

Answer:

The speed of student is 17.634 miles per hour.

Step-by-step explanation:

We need to find the speed of student in miles per hour.

Distance covered by student = 50 yards

We know that there are 0.000568182 miles in 1 yard.

Thus, the student covered

50\times 0.000568182 = 0.0284091~ miles

Time taken by the student = 5.8 second

We need to convert second into hours. There are 3600 seconds in 1 hour.

Time taken by student

\displaystyle\frac{5.8}{3600} = 0.001611~ hours

Formula:

Speed = \displaystyle\frac{\text{Distance covered}}{\text{Time taken}}

Speed = \displaystyle\frac{0.0284091}{0.001611} = 17.634\text{ miles per hour}

Thus, the speed of student is 17.634 miles per hour.

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It costs twelve dollars to get in to the fair. Tickets for rides cost extra and are d dollars each,
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I think it’s 20d-$12
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6 0
3 years ago
NEED ASAP Which line is parallel to the line y=4x-2?
Umnica [9.8K]

Answer:

y = 4x + 1

Step-by-step explanation:

Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope

Standard form of an equation is y = mx + b

Compare;

mx = 4x

m = 4

Since the slope of the given equation is 4, the required equation must also have a slope of 4

Since we are not given an option, we can assume any equation with a slope of 4

y = 4x + 1 will be parallel to the given equation since they both have the same slope

<em>Note that the equation can be different so far they have the slope of 4</em>

8 0
3 years ago
How do you find the equation for the line that is parallel to the line y=2/3x-7 and passes through the point (3,-1)
Debora [2.8K]

parallel lines have the same exact slope hmmm what's the slope of y = 2/3x-7 anyway? well, low and behold, is already in slope-intercept form, therefore

\bf \stackrel{\textit{slope-intercept form}}{y=\stackrel{slope}{\cfrac{2}{3}}x-7}.


so we're really looking for the equation of a line whose slope is 2/3, and runs through 3, -1.


\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})~\hspace{7em} slope =  m\implies \cfrac{2}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=\cfrac{2}{3}(x-3) \\\\\\ y+1=\cfrac{2}{3}x-2\implies y=\cfrac{2}{3}x-3

3 0
3 years ago
Find the area of the figure. <br><br> A = <br><br> Is it m, m2, or m3
enot [183]

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

5 0
3 years ago
Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
Makovka662 [10]

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

6 0
3 years ago
Read 2 more answers
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