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Troyanec [42]
3 years ago
9

Help me please 52 pts will mark brainlist

Mathematics
2 answers:
labwork [276]3 years ago
3 0

Answer:

D 7x( x^2y) ^1/3

Step-by-step explanation:

5x (x^2y)^1/3 +2 (x^5y)^1/3

We can simplify the second term

2 (x^5y)^1/3 = 2 (x^3 * x^2y) ^1/3

We know that (a*b) ^c = a^c * b^c

2 (x^3 * x^2y) ^1/3 = 2 (x^3 )^1/3*( x^2y) ^1/3

                                 2*x*( x^2y) ^1/3

Replacing this into the original equation

5x (x^2y)^1/3 +2x( x^2y) ^1/3

The term inside the cube root is the same, so we can add the terms on the outside

(5x+2x) 2x( x^2y) ^1/3

(7x)( x^2y) ^1/3

xeze [42]3 years ago
3 0

Answer:

Option 4

Step-by-step explanation:

5x(x²y)^⅓ + 2(x²y × x³)^⅓

5x(x²y)^⅓ + 2x(x²y)^⅓

7x(x²y)^⅓

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Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is 9\sqrt{2}

Step-by-step explanation:

The given function is f(x)=3(\sqrt{18})^x.

To find the initial value, we put x=0 into the function:  

f(0)=3(\sqrt{18})^0.

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The initial value is actually 3.

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The range of this function refers to all values of y for which the function is defined.

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The simplified base is 3\sqrt{18}=3\sqrt{9\times2}.

3\sqrt{18}=3\sqrt{9}\times\sqrt{2}

3\sqrt{18}=3\times3\times\sqrt{2}

3\sqrt{18}=9\sqrt{2}

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