<span>Dawn was at 6 am.
Variables
a = distance from a to passing point
b = distance from b to passing point
c = speed of hiker 1
d = speed of hiker 2
x = number of hours prior to noon when dawn is
The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as
a = cx = 9d
cx = 9d
x = 9d/c
The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as
b = dx = 4c
dx = 4c
x = 4c/d
We now have two expressions for x, set them equal to each other.
9d/c = 4c/d
Multiply both sides by d
9d^2/c = 4c
Divide both sides by c
9d^2/c^2 = 4
Interesting... Both sides are exact squares. Take the square root of both sides
3d/c = 2
d/c = 2/3
We now know the ratio of the speeds of the two hikers. Let's see what X is now.
x = 9d/c = 9*2/3 = 18/3 = 6
x = 4c/d = 4*3/2 = 12/2 = 6
Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am.
We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.</span>
Answer: $3.92
STEOS TO SOLUTION: take $19.62 and divide by 5
It should be the top left because the shaded area is below (or less than) the line -3/4x +1 and greater than the other line
4b + 22 = 5 (b + 4) - 1 (remove the parantheses)
4b + 22 = 5b + 20 - 1 (calculate)
4b + 22 = 5b + 19 (move the terms)
4b - 5b = 19 - 22 (collect like terms and calculate)
-b = -3 (change the signs)
<em>b = 3</em>
Answer:
You would go 45 miles.
Step-by-Step Explanation:
If you are going 60 mph you would be going 1 mile per minute
