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melamori03 [73]
1 year ago
15

Which expression is equivalent to 3x^-6y^-3 / 15x^2y^10? Assume x ≠ 0, y ≠ 0

Mathematics
1 answer:
9966 [12]1 year ago
3 0

\textsf {Simplifying the exponents :}

\mathsf {\frac{3x^{-6}y^{-3}}{15x^{2}y^{10}}}

\mathsf {\frac{1}{5x^{(2+6)}y^{(10+3)}}}

\mathsf {\frac{1}{5x^{8}y^{13}}}

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The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

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Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

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