Answer:
Rs 100x² + 150x - 100
Step-by-step explanation:
Area of the parking space = Length * Width
Area of the space = (2x-1)(x+2)
Expand
Area of the space = 2x² + 4x - x - 2
Area of the space = (2x²+3x - 2) sq. m
Since 1sq.m = Rs 50'
(2x²+3x - 2) sq. m= z
z = 50 (2x²+3x - 2)
z = 100x² + 150x - 100
hence the cost of the parking spsce is Rs.100x² + 150x - 100
-2.95, -2 11/12, 2 1/9, and then 2.95.
The answer is: 37,415 .
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GIven: 8,376 + ________ = 45,791 ;
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→ Solve for what goes in the blank.
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You would subtract "8,376" from "45,791" to get the answer:
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→ 45,791 − 8,376 = 37,415 ; → which is the answer.
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Answer: F / 0.15 = 100F / 15 = 20F / 3 ≈ 6.67F.
Explanation:
1) The three expresssions, F / 0.15; 15 F / 100; 3F / 20; are equivalent.
2) The number of figurines Kat owned last year may be expressed in terms of the number the of figurines purchased, F, this year, and the 15%, following this procedure:
- Call n the amount of figurines owned last year.
- F is the number of figurines purchased: F = 15%n = 0,15n
- Hence, you just need to clear F from the expression F = 0.15n
- Divide both sides by 0.15:
F / 0.15 = n or n = F / 0.15 (reflexive property)
- To prove the equialavence of the other expresssions you just have to use the properties of multiplication or division:
(F / 0.15) × (100 / 100) = 100F / 15
100F / 15 = (100/5)F / (15/5) = 20F / 3 ≈ 6.67F
Is it SV squared? Or times 2