Answer:
3053.5517 cm^3 ; 1/8
Step-by-step explanation:
Given the following :
Volume (V) of sphere = (4/3)πr^3 where r = radius
Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm
V = (4/3) × π × 9^3
V = 1.3333 × π × 729
V = 3053.5517 cm^3
When diameter(d) is reduced to half
d = d/2
Volume (V1) of sphere with diameter 'd' =
V1 = (4/3)π(d/2)^3
Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4
V2 = (4/3)π(d/4)^3
V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]
V1 / V2 = (d/2)^3 / (d/4)^3
V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]
V1 / V2 = 8 / 64
V1 / V2 = 1 / 8
Answer:
6.3 to the nearest 10th
Step-by-step explanation:
Hope this helped :)
Answer:
48∛9 ft²
Step-by-step explanation:
The length (L) and width (W) are given by:
![L = 4\sqrt[3]{24}\\ W= 6\sqrt[3]{3}](https://tex.z-dn.net/?f=L%20%3D%204%5Csqrt%5B3%5D%7B24%7D%5C%5C%20W%3D%206%5Csqrt%5B3%5D%7B3%7D)
Since this is a rectangular region, the area is given by:
![A=L*W=L \\A=4\sqrt[3]{24}* 6\sqrt[3]{3}\\A=24\sqrt[3]{72}\ ft^2](https://tex.z-dn.net/?f=A%3DL%2AW%3DL%20%5C%5CA%3D4%5Csqrt%5B3%5D%7B24%7D%2A%206%5Csqrt%5B3%5D%7B3%7D%5C%5CA%3D24%5Csqrt%5B3%5D%7B72%7D%5C%20ft%5E2)
The answer can be further simplified by factoring as follows:
![A=24\sqrt[3]{72} = \\A=24\sqrt[3]{2*2*2*3*3}= 24\sqrt[3]{2^3*9}\\A=48\sqrt[3]{9}\ ft^2](https://tex.z-dn.net/?f=A%3D24%5Csqrt%5B3%5D%7B72%7D%20%3D%20%5C%5CA%3D24%5Csqrt%5B3%5D%7B2%2A2%2A2%2A3%2A3%7D%3D%2024%5Csqrt%5B3%5D%7B2%5E3%2A9%7D%5C%5CA%3D48%5Csqrt%5B3%5D%7B9%7D%5C%20ft%5E2)
The exact area is its simplest form is 48∛9 ft²
Answer:
I think this is a true or false if so the answer is true:)
