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tensa zangetsu [6.8K]
2 years ago
6

Help pls :) have a great day everyone plshelp me

Mathematics
2 answers:
Vanyuwa [196]2 years ago
6 0

Answer:

(-3, -5)

Step-by-step explanation:

Here the vertex is also the minimum value; its x-coordinate is -3 and its y-coordinate is -5.  Thus, the vertex is at (-3, -5).  As stated above, this is the minimum value of the function.

Lostsunrise [7]2 years ago
4 0

The first step to solving almost any problem is to understand what the question is asking and what is given to us in order for us to solve for the question.  In this problem, we are given a graph and asked two questions.  One being what the coordinates of the vertex are and whether this parabola has a maximum or a minimum.  

Let's define what a vertex, maximum, and minimums are.

  • Vertex ⇒ Vertex is the point at which it either reaches the maximum or minimum.  This point can be easily defined as where the slope becomes flat.
  • Maximum ⇒ Maximum occurs when the vertex is at the top and the lines go down in a negative-y-direction.  Therefore with the vertex being at the top that would be considered a maximum as it's the largest point in the graph.
  • Minimum ⇒ Minimum occurs when the vertex is at the bottom and the lines go up in a positive-y-direction.  Therefore with the vertex being at the bottom that would be considered a minimum as it's the smallest point in the graph.

Now, looking at our problem we can see that our vertex is at the bottom therefore it would classify as a minimum.  Now that we know we have a minimum vertex, let us determine what the actual coordinates of the vertex are.  

We can see that we travel -3 in the x direction and -5 in the y direction which means that the coordinate for our vertex is (-3, -5) where the first number represents the x-value and the second number represents the y-value.

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Please helppppp!! Find the midpoint of the segment with the following end points (-2,7) and (2,3)
Margaret [11]

Answer:

\huge{ \boxed{ \bold{ \tt( \: 0 \:  ,5 \: )}}}

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

☞ First, Let's explore about Midpoint :

Midpoint of the segment simply means middle point of a line segment. Formula of Midpoint :

\boxed{ \sf{(x _{ \:  m \: } ,\: y_{m}) = ( \frac{x_{1} + x_{2}}{2}  ,\:  \frac{y_{1} + y_{2}}{2} )}}

where ,

  • ( \sf{x_{ \:  m \:  } ,\: y _{ \:  m \: })} = co-ordinates of the midpoint

  • ( \sf{ x_{ \: 1  \: }, \: y_{ \:  1 \: }}) = co-ordinates of the first point

  • \sf{(x _{ \:  2 \: } ,\: y_{ \:  2 \: })} = co-ordinates of the second point

The Midpoint Formula is used to find the exact center point between two defined points in a line segment.  The Midpoint formula is quite simple , so you should easily be able to remember it. It won't matter which point you pick to be the 'first" point you plug in. Just make sure that you're adding both an x to an x and a y to a y. Hence, keep in mind , in order to find the midpoint of a line segment, the first step is to add both ' x - co-ordinates' and divide it by 2 and then the second step is to add both ' y - co-ordinates ' and divide it by 2.

Now, Let's solve it!

☯ Question :

  • Find the midpoint of the segment with the following end points ( - 2 , 7 ) and ( 2 , 3 ).

☯ Step - by - step explanation :

Let P ( x , y ) divide the line joining the points A ( - 2 , 7 ) and B ( 2 , 3 ). Now, let :

  • A ( - 2 , 7 ) → ( x₁ , y₁ )
  • B ( 2 , 3 ) → ( x₂ , y₂ )

Apply midpoint formula , then plug the values and lastly simplify it :

\sf{ midpoint \:  =  \: ( \frac{x _{ \:  1 \: } + x _{ \:  2 \: }}{2}  ,  \:  \frac{y_{ \:  1 \: } + y _{ \:  2\: }}{2} })

➺ \sf{midpoint = ( \frac{ - 2 + 2}{2},   \:  \frac{7 + 3}{2} )}

➺ \sf{midpoint = ( \frac{0}{2} ,  \:  \frac{10}{2} )}

➺ \boxed{ \sf{  midpoint = ( \: 0 \: , 5})}

Hence , The midpoint of the segment with the end points A ( - 2 , 7 ) and B ( 2 , 3 ) is ( 0 , 5 ) .

Hope I helped!

Have a wonderful time ッ

~TheAnimeGirl ♡

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prisoha [69]

Answer:

The first incorrect justification is in step 2.

Step-by-step explanation:

<u>Step 2</u>. BC2 = AC • DC  

2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC

It's supposed to be AC ÷ BC not BC ÷ AC.

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