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2 years ago

5x + 2 + 3x + 5 = ?

Mathematics

1 answer:

Mama L [17]2 years ago

8 0

Answer: 8x + 7 = ?

Step-by-step explanation: There isn't anything on the other side so all I can do is simplify the left.

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$14.00 for 7 minutes<br> Unit rate

babunello [35]

Answer:

$2/min

Step-by-step explanation:

14 ÷ 7 = 2

Therefore, $2 per minute.

5 0

3 years ago

Read 2 more answers

Find the area of the following shape. (8 points)<br><br> what is the answer?

Ivenika [448]

Answer:

72 square units

Step-by-step explanation:

Identify the height
Identify the length
Multiply those two together
That is your answer

H = 9 units

L = 8 units

A = H × L

A = 9 × 8

A = 72 square units

8 0

2 years ago

What is the correct Algebraic Inequality for the given graph?<br>plsss help

Anna71 [15]

Answer:

X < 9

The hallow circle means just greater than or less than

The numberline is pointing downwards showing that 9 is greater than x(unknown value)

The point is also on 9

6 0

2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

In the year 2008, a person bought a new car for $23500. For each consecutive year after that, the value of the car depreciated b

Ksivusya [100]

Answer:

$17131.50

Step-by-step explanation:

23500 decrease 10% =

23500 × (1 - 10%) = 23500 × (1 - 0.1) = 21150

21150 decrease 10% =

21150 × (1 - 10%) = 21150 × (1 - 0.1) = 19035

19035 decrease 10% =

19035 × (1 - 10%) = 19035 × (1 - 0.1) = 17131.5

7 0

2 years ago